2nd Part of the Course
Please post any questions relating to material that was covered on the 2nd test as comments on this message.
Learn to solve mass transfer and separation process problems.
(This is NOT a weight loss website !)
12 Comments:
I was looking at Midterm 2, and got 4 points taken off on my graph for Pmin. But on your graph, it's the exact same spot. I've seen this on at least one other exam, so I'm guessing this might have been a common thing. If you can recall this as a common error, what were those 4 points taken off for?
A little more to that question:
On your graph, you connect Pmin, E1 and R1. I don't understand why you did this. Should you be connecting P, E1 and R1? Why is this different?
1. what are the assumptions for the hunter-nash method?
2. for what conditions should the fenske equation be used with caution?
3. what is the best method for estimating the distribution of non key components at the actual refulx?
please help
does anyone know what the difference is between class 1 and class 2 separations according to underwood????
I forgot if there is an order to step off stages for a stripper/absorber. Does it matter and what is the order if it does.
I was looking that the Fall 2005 test and one of the reading questions talks about "breakthrough time for an adsorption column." (question c) I don't remember talking about this? did we cover it?
duck tail 11:26 PM:
It is hard to say for sure, but MANY people located Pmin by drawing line SRN correctly but then drawing a line through F and the plait point. This is not correct. Pmin lies on line SRN where the tie line crosses it. In this case because we are on the extract side of hte plait point, we wnat the tie line that crosses closes to S. It turns out that the top tie-line is the winner.
I would have to look at your test to say exactly how I came up with -4 points.
duck tail 11:30 PM:
I connected F- E1,min - Pmin and then F - E1 - P. Pmin corresponds to the minimum solvent flow rate and P corresponds to the actual solvent flow rate.
finals are fun:
The assumptions for the Hunter-Nash Method are:
1- Ternary system
2- Type 1 system: Solute is infinitely soluble in both the solvent and the carrier (only the carrier-solvent exhibit partial miscibility).
3- Isothermal operation
4- P is high enough that no vapor phase forms
5- Continuous, countercurrent operation
help help help:
That is a fairly subtle question.
In a class 1 separation, there is just one pinch point. These are easier to solve. Use eqns 9-21 to 9-23.
In a class 2 separations, there are 2 pinch points. This is more complex and requires you to solve for values of theta in Eqn 9-29.
delicious bass:
Order ? Do you mean top to bottom as opposed to bottom to top ? Either way will do, but you must always begin and end on the operating line/curve.
If I didn't answer the right question, please post it again with more details.
oscar:
We did dicuss this, but we called it the "break point" instead of "breakthrough time". Check out slides 10 & 11 in lecture 9 PPT from 10/16.
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