Mass Transfer Test #1
Please post any questions you have about Test #1 as comments to this post.
Best of luck on the test !
Best of luck on the test !
posted by Dr. B at 4:40 PM
Thursday, October 26, 2006
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12 Comments:
On Spring 1999 test, the first problem is similar to what we did in our HW, but backward. Little "a" = Area for interfacial mass transfer/ volume of packed bed. In the volume lies the variable we want to find. Okay, so that's all good, but how? I know that big Ky = ky because it's pure water. How do I work this problem?
any solutions to the sample exam? i can't check if i actually got the right soln
Do we need to have all of the equations for finding diffusivity on our note sheet or just the one's in the lecture?
grrr:
Use the Henry's Law constant from the figure to evaluate (ybulk-y*)LM.
Use material balances to evaluate the MT rate, nA.
nA = NA*AMT = (K'ya)*Vbed*(ybulk-y*)LM
Solve for Vbed.
Use Vbed to solve for L (knowing the Dcolumn).
GL tomorrow!
anonymous:
I posted the answers on the downloads page but I won't post the solutions for reasons I explained in one of the sections of class today. Sorry, bud. I will give you intermediate answers here if that will help you.
dr. holt:
That is a tough call since there were SO MANY in the book. Be safe, go for all of them, But none of the tables or figures associated with the equations. Sorry, but that is the easy way out for me.
jim:
What worked great ?
Yep, the answers are there. Thank you for telling anonymous about them.
I'll be back here one more time later tonight.
For LLE, with the equilateral triangle diagrams and stuff, the extract and raffinate are 2 phases in equilibrium. Since they would both be liquid, how are they separated? Are they immiscible, like oil and water? If there is a point outside of the "dome" (area with tie lines), then would there only be one phase, so no possibility of separation?
Yes the raffinate and extract on opposite ends of the tie lines are two liquid phases that exist in equilibrium with each other, like oil and water.
Yes, the two liquids are different phases with different composition and usually different density. The phases do not dissolve in each other. We usually say two chemicals are immiscible or in this case the carrier and solvent are partially miscible. Partially miscible means that some carrier dissolves in the solvent and some of the solvent dissolves in the carrier.
I hope this helps.
OMG, what the hell is this jd thing?? Someone told me "the j factor". That is way too vague for comfort.
dr. O:
Yep, jD is the j-factor. You can learn more about it in the textbook...pages 99-100. It is part of the Chilton-Colburn Analogy.
I hope that helps.
Gnite.
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