HW 5 - p 6.8 - Graphical Analysis of the Absorption of Acetone in a Tray Tower - 7 pts
95% of the acetone in an 85 vol% air stream is to be absorbed by countercurrent contact with pure water in a valve-tray column with an expected overall tray efficiency of 50%. The column will operate essentially at 20oC and 101 kPa pressure.
Calculate:
a) The minimum value of L’/V’, the ratio of moles of water per mole of air.
b) The number of equilibrium stages required using a value of L’/V’ of 1.25 times the minimum.
c) The concentration of acetone in the exit water.
Feed flow rate can be taken to be 100kmol/h.
Calculate:
a) The minimum value of L’/V’, the ratio of moles of water per mole of air.
b) The number of equilibrium stages required using a value of L’/V’ of 1.25 times the minimum.
c) The concentration of acetone in the exit water.
Feed flow rate can be taken to be 100kmol/h.
posted by Dr. B at 2:42 PM
9 Comments:
does the comment about tray efficiency affect any of the calculations in this problem? is the equilibrium curve based on the 50% tray efficiency?
..so how do get part (a) of this question?
Karen:
Yes, the overall tray efficiency is important. This means that each tray provides the equivalent of one half of an equilibrium stage. So, Ntrays = Nsatges / EO = 2 Nstages.
I do not know what you mean when you ask if the equilibrium curve based on the 50% tray efficiency, but the equilibrium curve was generated without using the overall efficiency.
Anon:
You contruct an operating line on the XY Diagram that starts at {X0, Y1} and has the minimum slope possible while still reacing YN+1. Calculate the slope of this operating line (L'min/G') and use it to compute L'min.
This comment has been removed by the author.
please can i have the solution ??
it is urgent .
Hello Omtango,
I am sorry it took so long for me to reply. I am happy to answer
questions, but I am not willing to distribute solutions.
Best of luck,
Dr. B
how to solve the part b of this question?? pls reply
Cual es la solución de ese ejercicio??
Post a Comment
<< Home